Determine the amount of heat needed to evaporate 50 grams of water with a temperature of 50 degrees.
| July 24, 2021 | education
Initial data: m (mass of water) = 50 g (0.05 kg); t0 (water temperature) = 50 ºС.
Constants: C (specific heat) = 4200 J / (kg * ºС); t (beginning of the vaporization process) = 100 ºС; L (specific heat of vaporization) = 2.3 * 10 ^ 6 J / kg.
1) Heating: Q1 = C * m * (t – t0) = 4200 * 0.05 * (100 – 50) = 4200 * 0.05 * 50 = 10500 J.
2) Evaporation: Q2 = L * m = 2.3 * 10 ^ 6 * 0.05 = 115000 J.
3) Required heat: Q = 10500 + 115000 = 125500 J.
Answer: You will need 125500 J of heat.
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