Determine the Archimedean force acting on a cork lifebuoy with a volume of 30 dm3

Determine the Archimedean force acting on a cork lifebuoy with a volume of 30 dm3 in a cube if it is submerged by one third of the water

To find out the Archimedean force acting on the indicated cork lifebuoy, consider the formula: FА = ρw * g * Vlim = ρw * g * V / 3.

Const: ρw – water density (ρw = 1000 kg / m3; we consider that the lifebuoy is in fresh water and); q – acceleration of gravity (approx. q ≈ 10 m / s2).

Data: V is the volume of the indicated cork lifebuoy (V = 30 dm3 = 3 * 10-2 m3).

Let’s make a calculation: FA = ρw * g * V / 3 = 1000 * 10 * 3 * 10-2 / 3 = 100 N.

Answer: An Archimedean force of 100 N should act on the indicated cork lifebuoy.