Determine the current power in an electrolytic bath for the production of aluminum if 15 kg of aluminum are produced in it in 1 hour. Voltage at the terminals of the electrodes 4.8 V
Data: t (duration of the current in the electrolytic bath) = 1 hour (3600 s); m (mass of aluminum produced) = 15 kg; U (voltage at the terminals of the electrodes) = 4.8 V.
Reference data: k (electrochemical equivalent of aluminum) = 0.093 * 10 ^ -6 kg / C.
1) Determine the current in the electrolytic bath: I = m / (k * t) = 15 / (0.093 * 10 ^ -6 * 3600) = 44 803 A.
2) Current power in the bath: P = U * I = 4.8 * 44803 ≈ 215 * 10 ^ 3 W (215 kW).
Answer: The current power in the electrolytic bath is 215 kW.
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