Determine the current power in an electrolytic bath for the production of aluminum if 15 kg of aluminum

Determine the current power in an electrolytic bath for the production of aluminum if 15 kg of aluminum are produced in it in 1 hour. Voltage at the terminals of the electrodes 4.8 V

Data: t (duration of the current in the electrolytic bath) = 1 hour (3600 s); m (mass of aluminum produced) = 15 kg; U (voltage at the terminals of the electrodes) = 4.8 V.

Reference data: k (electrochemical equivalent of aluminum) = 0.093 * 10 ^ -6 kg / C.

1) Determine the current in the electrolytic bath: I = m / (k * t) = 15 / (0.093 * 10 ^ -6 * 3600) = 44 803 A.

2) Current power in the bath: P = U * I = 4.8 * 44803 ≈ 215 * 10 ^ 3 W (215 kW).

Answer: The current power in the electrolytic bath is 215 kW.




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