Determine the efficiency of an ideal heat engine if the temperature of the heater is 400 K
| September 21, 2021 | education
Determine the efficiency of an ideal heat engine if the temperature of the heater is 400 K and the temperature of the refrigerator is 300 K.
Given: T1 (heater temperature of the heat engine under consideration) = 400 K; T2 (temperature that the refrigerator has) = 300 K.
The efficiency of the considered ideal heat engine can be calculated using the formula: η = ((T1 – T2) / T2) * 100%.
Calculation of efficiency: η = ((400 – 300) / 400) * 100% = 0.25 * 100% = 25%.
Answer: The efficiency is 25%.
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