Determine the flight range of a ball thrown from the ground at an angle of 30 ° to the horizon, if the flight time was 6 s.

The total time of movement when moving at an angle to the horizon is:
t = 2V * sin a / g = V / g
Hence, V = t * g
Range L:
L = V ^ 2 * sin2a / g = t ^ 2 * g ^ 2 * sin 60 / g = t ^ 2 * g * sqrt (3) /2=36*10*0.85=360*0.85=288+18= 306m
Answer: L = 306m



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