Determine the force with which water acts on a square plug with a cross-sectional area of 50 cm2, if the distance from the plug to the water level in the tank is 4 m
Initial data: S (cross-sectional area of a square plug) = 50 cm2 (in SI S = 50 * 10-4 m2); h (distance from plug to water level) = 4 m.
Reference values: ρw (density of water in the tank) = 1000 kg / m3; g (acceleration due to gravity) ≈ 10 m / s2.
The force of water pressure on a square plug can be expressed from the formula: P = F / S, whence F = P * S = ρw * g * h * S.
Let’s calculate: F = 1000 * 10 * 4 * 50 * 10-4 = 200 N.
Answer: Water acts on a square plug with a force of 200 N.
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