# Determine the mass fraction of sodium chloride in the solution obtained by draining 50 g of a solution

**Determine the mass fraction of sodium chloride in the solution obtained by draining 50 g of a solution with a mass fraction of 20% salt and 90 g of a solution with a mass fraction of 30%?**

1. Find the mass of sodium chloride in the first solution:

m1 (NaCl) = w1 (NaCl) * m1 (solution) = 0.2 * 50 = 10 g;

2.Calculate the mass of salt in the second solution:

m2 (NaCl) = w2 (NaCl) * m2 (solution) = 0.3 * 90 = 27 g;

3.Calculate the mass of the total solution and the total mass of the salt:

mtotal (solution) = m1 (solution) + m2 (solution) = 50 + 90 = 140 g;

mtot (NaCl) = m1 (NaCl) + m2 (NaCl) = 10 + 27 = 37 g;

4.determine the mass fraction of salt in the resulting solution:

wpol (NaCl) = mtot (NaCl): mtot (solution) = 37: 140 = 0.2643 shares or 26.43%.

Answer: 26.43%.