Determine the mass fraction of water of crystallization in barium chloride dihydrate BaCl2 * 2H2O

The mass of the crystalline hydrate of barium chloride BaCl2 * 2H2O = m (Ba) + m (Cl) * 2 + m (H2O) * 2 = 137 + 35.5 * 2 + 18 * 2 = 244 grams. 244 grams of barium chloride contains 36 grams of crystalline water, therefore, according to the proportion: 244 grams – 100%, and 36 grams – X. Hence X = 14.75% – so many percent of water of crystallization is contained in barium chloride dihydrate.



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