Determine the mass of 10% hydrochloric acid required for the reaction with 17 g of silver nitrate.

When silver nitrate interacts with hydrogen chloride, an insoluble silver chloride salt is synthesized.

The process is described by the following equation:

AgNO3 + HCl = AgCl + HNO3;

1 mole of silver nitrate reacts with 1 mole of hydrogen chloride. In this case, 1 mol of silver chloride, insoluble in water, is synthesized.

Let’s calculate the chemical amount of the available substance.

M AgNO3 = 108 + 14 + 16 x 3 = 170 grams / mol;

N AgNO3 = 17/170 = 0.1 mol;

0.1 mol of nitrate will react with 0.1 mol of acid. This synthesizes 0.1 mol of silver chloride.

M HCl = 1 + 35.5 = 36.5 grams / mol;

m HCl = 0.1 x 36.5 = 3.65 grams;

m 10% solution = 3.65 / 0.1 = 36.5 grams;