Determine the mass of 30 liters of oxygen at a pressure of 5 * 10 ^ 5 N / m ^ 2 and a temperature of 27 degrees Celsius.

Initial data: V (oxygen volume) = 30 l (30 * 10 ^ -3 m3); P (oxygen pressure) = 5 * 105 N / m2 (5 * 10 ^ 5 Pa); T (absolute temperature of oxygen) = 27 ºС (300 K).

Constants: M (molar mass of oxygen) = 0.032 kg / mol; R (universal gas constant) = 8.31 J / (mol * K).

The mass of 30 liters of oxygen is determined by the formula (Mendeleev-Clapeyron’s law): P * V = (m / M) * R * T, whence m = P * V * m / (R * T).

Calculation: m = 5 * 10 ^ 5 * 30 * 10 ^ -3 * 0.032 / (8.31 * 300) ≈ 0.193 kg (193 g).