# Determine the mass of 5 liters of oxygen at atmospheric pressure and a temperature of 20 C

March 31, 2021 | education

| Under conditions that differ from standard ones, Mendeleev Clapeyron’s law is used to determine the parameters of gases:

p * V = n * R * T, where

p – gas pressure, in Pa

V – gas volume, in m3

n is the amount of gas substance, in mol

T – temperature, in K

R – universal gas constant, R = 8.31 J / (mol * K)

Let’s bring our parameters to the units of the formula.

p = 101325 Pa, V = 5 l = 0.005 m3, T = 20 ° C = 293 K.

Calculate n = p * V / (R * T) = 101325 * 0.005 / (8.31 * 293) = 0.208 mol

Find the mass of oxygen m = n * M, where M = 32 g / mol is the molar mass of oxygen

m = 0.208 * 32 = 6.66 g

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