The calcium oxidation reaction is described by the following chemical reaction equation:
Ca + ½ O2 = CaO;
From 1 mole of calcium, 1 mole of calcium oxide is synthesized.
Let’s calculate the chemical amount of a substance contained in 12 grams of calcium.
M Ca = 40 grams / mol;
N Ca = 12/40 = 0.3 mol;
The same amount of calcium oxide will be obtained.
We calculate the weight of 0.3 mol of calcium oxide.
M CaO = 40 + 16 = 56 grams / mol;
m CaO = 0.3 x 56 = 16.8 grams;
0.15 mol of oxygen will enter into the reaction.
Its weight will be:
m O2 = 0.15 x 32 = 4.8 grams
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