Determine the mass of nitric acid that can be obtained from 11.2 liters of ammonia.

To solve the problem, make up the equation:
V = 11.2 liters. X g -?
1. NH3 + 2O2 = HNO3 + H2O – OBP, nitric acid was obtained;
2. Calculations:
M (HNO3) = 63 g / mol;
M (NH3) = 17 g / mol.
3. Proportion:
1 mole of gas at normal level – 22.4 liters;
X mol (NH3) -11.2 l. hence, X mol (NH3) = 1 * 11.2 / 22.4 = 0.5 mol;
Y (HNO3) = 0.5 mol since the amount of these substances according to the equation is 1 mol.
4. Find the mass of the product:
m (HNO3) = Y * M = 0.5 * 63 = 31.5 g.
Answer: nitric acid with a mass of 31.5 g was formed.