Let’s find the amount of ethanal substance СН3СОН.
M (CH3CHOH) = 44 g / mol.
n = m: M.
n (CH3COH) = 50 g: 44 g / mol = 1.136 mol.
Let’s compose the reaction equation, find the quantitative ratios of substances.
CH3COOH + Ag2O = CH3COOH + 2Ag ↓.
According to the reaction equation, there is 2 mol of Ag per 1 mol of СН3СОН. The substances are in quantitative ratios of 1: 2.
n (Ag) = 2n (СН3СОН) = 1.136 × 2 = 2.27 mol.
Let’s find the mass Ag.
M (Ag) = 108 g / mol.
m = n × M,
m = 2.27 mol × 108 g / mol = 245.16 g.
Answer: 245.16 g.
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