Determine the mass of steel that can be melted in a furnace with an efficiency equal

Determine the mass of steel that can be melted in a furnace with an efficiency equal to 45%, burning 1.8 tons of coal.

Efficiency = 45%.

mu = 1.8 t = 1800 kg.

qу = 2.7 * 10 ^ 7 J / kg.

λst = 0.84 * 10 ^ 5 J / kg.

mst -?

Let us write down the definition for efficiency = Qst * 100% / Qy, where Qst is the amount of heat required to melt steel, Qy is the amount of heat released during the combustion of coal.

Qу = qу * mу.

Qst = λst * mst.

Efficiency = λst * mst * 100% / qу * mu.

The formula for determining steel will take the form: mst = efficiency * qу * mу / λst * 100%.

mst = 45% * 2.7 * 10 ^ 7 J / kg * 1800 kg / 0.84 * 10 ^ 5 J / kg * 100% = 260357 kg.

Answer: coal can melt mst = 260357 kg of steel.



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