The reaction of interaction of aluminum with sulfuric acid is described by the following chemical equation:
2Al + 3H2SO4 (diluted) = Al2 (SO4) 3 + 3H2;
When 2 metal molecules dissolve, 3 hydrogen molecules are released.
Let’s calculate the chemical amount of a substance in 270 grams of metal.
M Al = 27 grams / mol;
N Al = 270/27 = 10 mol;
When dissolving such an amount, 10/2 x 3 = 15 mol of acid will be needed and 10/2 x 3 = 15 mol of hydrogen will be released.
Let’s calculate the mass of sulfuric acid:
M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;
m H2SO4 = 98 x 15 = 1 470 grams;
Let’s calculate the volume of hydrogen:
1 mole of ideal gas normally takes on a volume of 22.40 liters.
V H2 = 15 x 22.40 = 336 liters;
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