Determine the mass of the precipitate that forms as a result of the reaction between the sulfuric acid solution and the barium chloride solution, if the mass of barium chloride in the initial solution is 4, 16 g.
When barium chloride interacts with sulfuric acid, an insoluble salt of barium sulfate is synthesized.
The process is described by the following equation:
BaCl2 + H2SO4 = BaSO4 + 2HCl;
1 mole of barium chloride reacts with 1 mole of sulfuric acid. In this case, 1 mol of water-insoluble barium sulfate is synthesized.
Let’s calculate the chemical amount of the available substance.
M BaCl2 = 137 + 35.5 x 2 = 208 grams / mol;
N BaCl2 = 4.16 / 208 = 0.02 mol;
0.02 mol of barium chloride reacts with 0.02 mol of sulfuric acid. This synthesizes 0.02 mol of water-insoluble barium sulfate.
M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol;
The sediment weight will be:
m BaSO4 = 0.02 x 233 = 4.66 grams;
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