Determine the mass of the substance obtained if it is known that 0.5 mol of calcium oxide and 200 g of water

Determine the mass of the substance obtained if it is known that 0.5 mol of calcium oxide and 200 g of water have entered into the reaction. What substance is taken in excess? What mass of this substance will not react?

Given:
O (CaO) = 0/5 mol
m (H2O) = 200g
Decision:
CaO + H2O = Ca (OH) 2
m (CaO) = 0/5 * 56 = 28 g
m1 (H2O) = 28 * 18 \ 74 = 68
m2 (H2O) = 200-6 / 8 = 193.2 g
Answer: Excess water in 193.2 g



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