Determine the pressure at a depth of 0.6 m in water, kerosene, mercury.

According to Pascal’s law:
The hydrostatic pressure inside the liquid at any depth does not depend on the shape of the vessel in which the liquid is located, and is equal to the product of the density of the liquid, the acceleration of gravity and the depth at which the pressure is determined:
P = ρ * g * h, where ρ is the density of the liquid, g is the free fall acceleration of a body raised above the Earth g = 9.8 m / s2, h is the depth of immersion in the liquid.
Let’s find the density of liquids in the reference book:
ρwater = 1000 kg / m³
ρkerosene = 800 kg / m³
ρmercury = 13600 kg / m³

Substituting the data into the formula for pressure, we get:
Pwater = ρwater * g * h = 1000 * 9.8 * 0.6 = 5880 Pa
Pkerosene = ρkerosene * g * h = 4704 Pa
Pmercury = ρmercury * g * h = 79968 Pa

Answer: Pressure in water 5880 Pa, in kerosene 4704 Pa, in mercury 79968 Pa.

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