Determine the pressure exerted on the floor by the cabinet, the weight of which is 800N
| July 24, 2021 | education
Determine the pressure exerted on the floor by the cabinet, the weight of which is 800N, and the surface area of one leg is 25 cm2.
Initial data: Psh (weight of the considered cabinet) = 800 N; S1 (surface area of one cabinet leg) = 25 cm2 (25 * 10 ^ -4 m2); we take n (the number of legs in the cabinet) = 4 pcs.
The pressure that the cabinet exerts on the floor is determined by the formula: P = F / S = Psh / 4S1.
Calculation: P = 800 / (4 * 25 * 10 ^ -4) = 80,000 Pa (80 kPa).
Answer: The cabinet exerts a pressure of 80 kPa on the floor.
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