Determine the pressure in the mine at a depth of h = 240m. The pressure on the Earth’s surface is p0 = 101.3 kPa.

Given:

P0 = 101.3 kPa = 101300 Pascal – pressure on the Earth’s surface;

H = 240 meters – the depth of the mine;

с = 12 / 133.3 m / Pa – dependence of atmospheric pressure on altitude.

It is required to determine the pressure at the bottom of the shaft P1.

P1 = P0 + dP = P0 + H / c = 101300 + 240 / (12 / 133.3) =

= 101300 + 240 * 133.3 / 12 = 101300 + 20 * 133.3 = 101300 + 2666 = 103,966 Pa = 104 kPa.

Answer: the pressure at the bottom of the mine will be 104 kPa.



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