Problem data: a (the length of the considered lead cube) = 10 cm (in SI a = 0.1 m).
Reference values: ρс (lead density) = 11300 kg / m3; g (acceleration due to gravity) ≈ 10 m / s2.
The pressure that the lead cube under consideration creates on the ground is calculated by the formula: P = F / S = m * g / a ^ 2 = ρс * V * g / a ^ 2 = ρс * a ^ 3 * g / a ^ 2 = ρс * a * g.
Let’s calculate: P = 11300 * 0.1 * 10 = 11300 Pa (11.3 kPa).
Answer: The lead cube in question exerts a pressure of 11.3 kPa on the ground.
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