Determine the specific heat of a substance if, when heating 1 kg of this substance from -10 degrees
| September 20, 2021 | education
Determine the specific heat of a substance if, when heating 1 kg of this substance from -10 degrees C to 0 degrees C, it took 21 kJ.
Initial data: m (mass of the heated substance) = 1 kg; t1 (initial temperature of the substance) = -10 ºС; t2 (final heating temperature of the substance) = 0 ºС; Q (required amount of heat) = 21 kJ (21 * 10 ^ 3 J).
You can determine the specific heat of a substance from the formula: Q = C * m * (t2 – t1) and C = Q / (m * (t2 – t1)).
Calculation: C = 21 * 10 ^ 3 / (1 * (0 – (-10)) = 2100 J / (kg * ºС), the substance is ice.
Answer: The specific heat capacity of a substance (ice) is 2100 J / (kg * ºС).
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