Determine the value of the acceleration due to gravity near the surface of the Moon, assuming the mass is equal
| September 22, 2021 | education
Determine the value of the acceleration due to gravity near the surface of the Moon, assuming the mass is equal to Ml = 7.35 * 10 ^ 19 tons, and the diameter Dl = 3500 km.
Free fall acceleration near the lunar surface can be calculated using the formula:
g = G * M / R², where G is the gravitational constant (G = 6.67 * 10 ^ -11 m³ / (kg * s²)), M is the mass of the Moon (M = 7.35 * 10 ^ 19 t = 7 , 35 * 10 ^ 22 kg), R is the radius of the Moon (R = 0.5D, where D is the diameter of the Moon (D = 3500 km = 3500 * 10³ m)).
Acceleration of gravity:
g = G * M / R² = 6.67 * 10 ^ -11 * 7.35 * 10 ^ 22 / (0.5 * 3500 * 10³) ² = 1.6 m / s².
Answer: Acceleration of free fall near the surface of the Moon is 1.6 m / s².
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