Determine the volume of a gas mixture of nitrogen and hydrogen, in which the mass fraction of hydrogen is 6.67 percent? and the number of hydrogen atoms is 2.69 * 10 ^ 23.
The amount of hydrogen in the mixture (a molecule contains two atoms):
2.69: 2: 6.02 = 0.223 mol, which corresponds to a mass of 0.223 * 2 = 0.447 g.
The mass of nitrogen in the mixture:
0.447: 0.0667 = 6.7 g, which corresponds to an amount of 6.7: 14 = 0.478 mol.
In total, the mixture contains 0.223 + 0.478 = 0.701 mol of gas, or 0.701 * 22.4 = 15.7 liters.
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