Determine the volume of carbon dioxide that is formed during the combustion of benzene with an amount of 3 mol.

The benzene combustion reaction is described by the following chemical equation:

C6H6 + 7.5 O2 = 6CO2 + 3H2O;

To burn 1 mol of benzene, 7.5 mol of oxygen is required.

To burn 3 mol of benzene, 7.5 x 3 = 22.5 mol of oxygen is required.

Let’s calculate its volume.

1 mole of ideal gas normally takes on a volume of 22.40 liters.

V O2 = 22.5 x 22.40 = 504 liters;

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