The benzene combustion reaction is described by the following chemical equation:
C6H6 + 7.5 O2 = 6CO2 + 3H2O;
To burn 1 mol of benzene, 7.5 mol of oxygen is required.
To burn 3 mol of benzene, 7.5 x 3 = 22.5 mol of oxygen is required.
Let’s calculate its volume.
1 mole of ideal gas normally takes on a volume of 22.40 liters.
V O2 = 22.5 x 22.40 = 504 liters;
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