Determine the volume of gas released by the interaction of 4.6 grams of sodium with hydrogen chloride.

Let’s implement the solution:
Let’s compose the reaction equation: 2Na + 2HCl = 2NaCl + H2 – ОВР, hydrogen evolved
Determine the number of moles of sodium by the formula: Y (Na) = m (Na) / M (Na);
Y (Na) = 4.6 / 22.9 = 0.2 mol;
Let’s write the proportion according to the reaction equation:
0.2 mol (Na) – X mol (H2);
X mol (H2) = 0.2 * 1/2 = 0.1 mol;
Let’s calculate the volume of hydrogen according to Avogadro’s law:
V (H2) = 0.1 * 22.4 = 2.24 liters.
Answer: when sodium interacts with hydrogen chloride, 2.24 liters of hydrogen was released.