Determine the work of the electric current at a current of 5.5A, if the consumer resistance is 1200 Ohm.

Determine the work of the electric current at a current of 5.5A, if the consumer resistance is 1200 Ohm. And he worked for 30 seconds. Calculate its power consumption.

The work of the current is directly proportional to the square of the current strength, resistance and time:
A = I ^ 2 * R * t = 1089kJ
And the power P is directly proportional to the square of the current and resistance:
P = I ^ 2 * R = 36.3kW



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