During the hydrolysis of starch weighing 81 kg, glucose is formed, the amount of the substance …


m (C6H10O5) = 81 kg,

n (C6H12O6) -?


Find the amount of starch substance C6H10O5.

n = m: M.

M (C6H10O5) = 162 kg / kmol.

n = 84 kg: 162 kg / kmol = 0.5 kmol.

(C6H10O5) n + nH2O → n C6H12O6.

n (C6H10O5) = n (C6H12O6) = 0.5 kmol.

Answer: 0.5 kmol.

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