During the hydrolysis of starch weighing 81 kg, glucose is formed, the amount of the substance …
| March 28, 2021 | education
Given:
m (C6H10O5) = 81 kg,
n (C6H12O6) -?
Decision:
Find the amount of starch substance C6H10O5.
n = m: M.
M (C6H10O5) = 162 kg / kmol.
n = 84 kg: 162 kg / kmol = 0.5 kmol.
(C6H10O5) n + nH2O → n C6H12O6.
n (C6H10O5) = n (C6H12O6) = 0.5 kmol.
Answer: 0.5 kmol.
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