# Electrons moving with acceleration acquire a speed of 8 * 10 ^ 6 m / s at the anode of the vacuum diode.

Electrons moving with acceleration acquire a speed of 8 * 10 ^ 6 m / s at the anode of the vacuum diode. what is the voltage between the anode and the cathode in this case? consider the initial velocity of electrons to be zero. the mass of the electron is 9.1 * 10 ^ -31 kg and the modulus of its charge is e1.6 * 10 ^ -19 cells

V0 = 0 m / s.

V = 8 * 10 ^ 6 m / s.

q = 1.6 * 10 ^ -19 Cl.

m = 9.1 * 10 ^ -31 kg.

U -?

The work of the electric field A on the movement of the electric charge q is equal to the change in the kinetic energy of the charge ΔEk: A = ΔEk.

We express the work of the electrostatic field A by the formula: A = q * U, where q is the amount of charge, U is the voltage between the anode and cathode.

ΔEk = Ek – Ek0 = m * V ^ 2/2 – m * V0 ^ 2/2 = m * V ^ 2/2.

q * U = m * V ^ 2/2.

U = m * V ^ 2/2 * q.

U = 9.1 * 10 ^ -31 kg * (8 * 10 ^ 6 m / s) ^ 2/2 * 1.6 * 10 ^ -19 C = 182 V.

Answer: the voltage between the anode and cathode is U = 182 V. One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.