Find the angle ACD of a rectangular trapezoid ABCD if the acute angle D of the trapezoid is 30 and the diagonal AC makes an angle of 20 with the lateral side AB.
Since the trapezoid is rectangular, the angle BAD = ABC = 90.
Then the angle CAD = (BAD – BAC) = (90 – 20) = 70.
Consider triangle ACD. The sum of the interior angles of a triangle is 180, then:
Angle ACD = (180 – CAD – ADC) = (180 – 70 – 30) = 100.
Answer: The angle ACD is 100.
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