Find the angles of an isosceles trapezoid if the acute angle is 2/3 of the obtuse angle

In an isosceles (isosceles) trapezium, the sides are equal. The left corners are respectively equal to the right corners. The sum of the acute and obtuse angles is 180 °. Let’s solve the problem using the equation, where:

2x ° – acute angle of the trapezoid;

3x ° – obtuse angle of the trapezoid;

Then the sum of the angles:

2x + 3x = 180 °;

5x = 180;

x = 180/5;

x = 36;

2x = 2 * 36 = 72 ° – acute angle of the trapezoid;

3x = 3 * 36 = 108 ° – obtuse angle of the trapezoid.

Answer: 72 °, 72 °, 108 °, 108 °