Find the area and perimeter of a rectangle if its length is 17 dm and its width is 8 dm less than its length.

1. What is the width of the rectangle?
17 – 8 = 9 dm.
2. Find the area of the rectangle.
17 * 9 = 153 sq. Dm.
3. Find the perimeter of the rectangle.
(17 + 9) * 2 = 52 dm.
Answer: The area of the rectangle is 153 sq. Dm. Perimeter – 52 dm.

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