1. The length of the leg AB is 12 units. The length of the BC hypotenuse is 13 units. Angle A is straight. S is the area of the triangle.
2. We calculate the length of the AC – the second leg of the triangle. For this we use the theorem
AC = √BC² – AB² = √13² – 12² = √169 – 144 = √25 = 5 units.
3. S = 1 / 2AC x AB = 1/2 x 12 x 5 = 30 units of measurement².
Answer: S is equal to 30 units of measurement².
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