Find the area of an isosceles trapezoid if its lateral side is 41 cm, and the bases are 22 cm and 40 cm

S = 1/2 (BC + AD) * BH; VN – height;

BH = √ (AB² – AH²); AH = 1/2 (AD – BC) = 1/2 (40 -22) = 9 (cm);

BH = √ (41² – 9²) = √ (41 – 9) (41 + 9) = √1600 = 40 (cm);

S = 1/2 (22 + 40) * 40 = 1240 (cm²);



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