Find the area of an isosceles trapezoid in which; a) the height is exactly 5 cm of the base – 6 cm and 14 cm, respectively;

Find the area of an isosceles trapezoid in which; a) the height is exactly 5 cm of the base – 6 cm and 14 cm, respectively; b) the height is exactly 8 cm and the base is 5 cm and 7 cm, respectively;

The area of the trapezoid is equal to the product of the half-sum of its bases by the height:

S = (a + b) / 2 h.

a) let’s say that BC = 6 cm, AD = 14 cm, BH = 5 cm.Now we find the area of this trapezoid:

S = (BC + AD) / 2 · BH;

S = (6 + 14) / 2 5 = 50 cm2.

Answer: the area of this trapezoid is 50 cm2.

b) Suppose that BC = 5 cm, AD = 7 cm, BH = 8 cm.Let’s find the area:

S = (BC + AD) / 2 · BH;

S = (5 + 7) / 2 8 = 12/2 8 = 6 8 = 48 cm2.

Answer: the area of the trapezoid is 48 cm2.



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