Find the area of an isosceles triangle with side 17 cm and base 30 cm

S = 1/2 AC * BH, AH = 1/2 AC = 15 cm;

BH = √ (AB² – AH²) = √ (17² – 15²) = √64 = 8 (cm);

S = 1/2 * 30 * 8 = 120 (cm²).



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