# Find the area of the parallelepiped of the surface and the sum of the lengths of the edges of the cube

**Find the area of the parallelepiped of the surface and the sum of the lengths of the edges of the cube, the edge of which is 11cm, length 40cm, width 30, height 20.**

1) The surface area of a parallelepiped is equal to the sum of the areas of its faces. Since the length, width and height of the parallelepiped are, respectively, 40 cm, 30 cm and 20 cm, the sum of the areas of its faces is equal to:

S = 40 * 30 + 40 * 30 + 40 * 20 + 40 * 20 + 30 * 20 + 30 * 20 =

= 2 * (40 * 30 + 40 * 20 + 30 * 20) = 2 * (1200 + 800 + 600) = 2 * 2600 = 5200 cm².

2) The cube has 12 edges – 4 in the upper square, 4 in the lower one, and 4 connecting the upper and lower squares. Therefore, the sum of the lengths of the edges of a cube with a side of 11 cm is 12 * 11 cm = 132 cm.