Find the Derivative of the Function y = 3sinx + 4cosx

The derivative from the sum of the arguments is the sum of the derivatives from each of the arguments. To solve the problem, remember the derivatives of sin and cos:

(sinx) ‘= cosx;

(cos x) ‘= -sin x;

Hence:

y = 3sinx + 4cosx;

y ‘= (3sinx + 4cosx)’ = (3sinx) ‘+ (4cosx)’ = 3cosx – 4sinx.



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