Find the kinetic energy of a body weighing 3 kg, falling freely from a height of 6 m, at the moment when the body is at a height of 1 m from the earth’s surface.
To find the kinetic energy at the height h2, we write the energy conservation law:
mgh1 = mgh2 + mv ^ 2/2
2gh1 = 2gh2 + v ^ 2
V = sqrt (2gh1-2gh2) = sqrt (120-20) = 10 m / s
answer: 10 m / s
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