Find the mass and volume of ammonia that will result from the interaction of 20 grams of ammonium chloride and 7.4 grams of calcium hydroxide.
1. Let’s write down the reaction equation:
2NH4Cl + Ca (OH) 2 = CaCl2 + 2NH3 + 2H2O;
2.Calculate the chemical quantities of reactants:
n (NH4Cl) = m (NH4Cl): M (NH4Cl);
M (NH4Cl) = 14 + 4 + 35.5 = 53.5 g / mol;
n (NH4Cl) = 20: 53.5 = 0.3738 mol;
n (Ca (OH) 2) = m (Ca (OH) 2): M (Ca (OH) 2);
M (Ca (OH) 2) = 40 + 16 * 2 + 2 = 74 g / mol;
n (Ca (OH) 2) = 7.4: 74 = 0.1 mol;
3.the lack of calcium hydroxide, we determine from its data the amount of ammonia:
n (NH3) = n (Ca (OH) 2) * 2 = 0.1 * 2 = 0.2 mol;
4. find the mass and volume of ammonia:
m (NH3) = n (NH3) * M (NH3) = 0.2 * 17 = 3.4 g;
V (NH3) = n (NH3) * Vm = 0.2 * 22.4 = 4.48 dm3.
Answer: 3.4 g; 4.48 dm3.
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