Find the mass fractions of carbon, hydrogen and oxygen in the molecule of acetic acid CH3COOH.
| September 21, 2021 | education
1. Calculate the relative molecular weight of acetic acid:
Mr (CH3COOH) = 12 + 3 + 12 + 32 + 1 = 60;
2.Calculate the mass fractions of elements:
w (C) = 2 * Ar (C): Mr (CH3COOH) = 24: 60 = 0.4 or 40%;
w (H) = 4 * Ar (H): Mr (CH3COOH) = 0.0667 or 6.67%;
w (O) = 2 * Ar (O): Mr (CH3COOH) = 32: 60 = 0.5333 or 53.33%.
Answer: 40% C, 6.67% H, 53.33% O.
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