# Find the mass of barium nitrate obtained in the reaction between barium hydroxide and 60 g of a 40% nitric acid solution.

Let’s compose the reaction equation.
Ba (OH) 2 + 2 HNO3 -> Ba (NO3) 2 + 2 H2O.
We find the mass of nitric acid. We use the following formula.
W = mr.w. / mr-ra × 100%.
m (HNO3) = 60 g × 0.4 = 24 g HNO3.
Further, we consider the molar mass of nitric acid.
M (НNO3) = 1 + 14 + 3 × 16 = 64 g / mol.
Next, we find the molar mass of barium nitrate.
М (Ba (NO3) 2) = 261 g / mol.
We find the mass of barium nitrate from the reaction equation.
24 g HNO3 – x g Ba (NO3) 2.
2 × 64 g / mol HNO3 – 261 g / mol Ba (NO3) 2.
X = 24 × 261 ÷ (2 × 64) = 48.9 g Ba (NO3) 2.
Answer: m (Ba (NO3) 2) = 48.9 g. One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.