Find the mass of barium sulfate obtained by reacting a solution containing 0.7 mol of barium

Find the mass of barium sulfate obtained by reacting a solution containing 0.7 mol of barium chloride with an excess of sulfuric acid.

Barium chloride salt reacts with sulfuric acid. This forms a water-insoluble barium sulfate salt, which precipitates. The reaction is described by the following chemical reaction equation.

BaCl2 + H2SO4 = BaSO4 + 2HCl;

Barium chloride reacts with sulfuric acid in equal molar amounts. In this case, an equal amount of insoluble salt is synthesized.

The chemical amount of barium chloride is.

N BaCl2 = 0.7 mol;

The same amount of barium sulfate will be synthesized.

Let’s calculate its weight.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol; m BaSO4 = 0.7 x 233 = 163.1 grams;