Find the mass of barium sulfate obtained by reacting a solution containing 0.7 mol of barium chloride with an excess of sulfuric acid.
Barium chloride salt reacts with sulfuric acid. This forms a water-insoluble barium sulfate salt, which precipitates. The reaction is described by the following chemical reaction equation.
BaCl2 + H2SO4 = BaSO4 + 2HCl;
Barium chloride reacts with sulfuric acid in equal molar amounts. In this case, an equal amount of insoluble salt is synthesized.
The chemical amount of barium chloride is.
N BaCl2 = 0.7 mol;
The same amount of barium sulfate will be synthesized.
Let’s calculate its weight.
M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol; m BaSO4 = 0.7 x 233 = 163.1 grams;
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