# Find the mass of magnesium that can react with 33.6 liters of oxygen.

Metallic magnesium is intensively oxidized by oxygen. The oxidation reaction is described by the following equation:

Mg + ½ O2 = MgO;

In this reaction, 1 oxygen atom is added to 1 magnesium atom and 1 magnesium oxide molecule is synthesized.

Let’s calculate the chemical (molar) amount of oxygen.

To do this, we divide its volume by the volume of 1 mole of gas.

N O2 = 33.6 / 22.4 = 1.5 mol;

With this amount of oxygen, 2 times more magnesium will react.

Let’s calculate its weight.

Let’s multiply the amount of the substance by the weight of 1 mole of the substance.

M Mg = 24 grams / mol; m Mg = 1.5 x 2 x 24 = 72 grams;

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