Let’s find the amount of substance NaOH.
n = m: M.
M (NaOH) = 40g / mol.
n = 15 g: 40 g / mol = 0.375 mol.
Let’s find the quantitative ratios of substances.
2NаОH + H2SO4 → Na2SO4 + 2Н2О.
For 2 mol of NaOH, there is 1 mol of Na2SO4.
Substances are in quantitative ratios of 2: 1.
The amount of Na2SO4 substance will be 2 times less than NaOH ..
n (Na2SO4) = ½ n (NaOH) = 0.375: 2 = 0.188 mol.
Let’s find the mass of Na2SO4.
m = n × M.
M (Na2SO4) = 142 g / mol.
m = 142 g / mol × 0.188 mol = 26.7 g.
Answer: 26.7 g.
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