Find the mass of sodium sulfate that is formed by the interaction of 65 g of sodium hydroxide with sulfuric acid
July 29, 2021 | education|
First, we write down the equation of reactions.
H2SO4 + 2NaOH -> Na2SO4 + 2H2O.
Next, we find the molar mass of sodium hydroxide.
M (NaOH) = 23 + 1 + 16 = 40 g / mol.
Find the molar mass of sodium sulfate.
M (Na2SO4) = 23 × 2 + 32 + 16 × 4 = 142 g / mol.
Next, we make up the proportion.
65 g NaOH – x g Na2 SO4.
2 × 40 g / mol NaOH – 142 g / mol Na2SO4.
x g = 65 × 142/80 = 115.375 g.
This means that 115.375 g of sodium sulfate is formed as a result.
Answer: m (Na2SO4) = 115.375 g.
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