Initial data: m (mass of an aluminum object) = 135 g.
Reference data: Na (Avogadro’s number) = 6.02 * 10 ^ 23 mol-1; M (molar mass of aluminum) = 27 g / mol.
The number of atoms in an aluminum object can be determined from the ratio: m / M = N / Na = ν, whence N = m * Na / M.
Let’s calculate: N = 135 * 6.02 * 10 ^ 23/27 = 30.1 * 10 ^ 23 atoms.
Answer: The number of atoms in an aluminum object is 30.1 * 1023.
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