Find the perimeter of a rectangle whose length is 24 cm and the width is 4 times shorter.

Let the length of the rectangle be a and the width b. Width 4 times shorter than length.

Solution:

1.a = 24 cm.

2.h = 24/4 cm.

h = 6 cm.

3. The perimeter of the rectangle is equal to the sum of all sides, a + a + b + b.

24 + 24 + 6 + 6 = 60 cm.

Answer: The perimeter of the rectangle is 60 centimeters.



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