Find the radius of a circle around a regular triangle whose area is 3√3.

Since, by condition, triangle ABC is regular, all its internal angles are equal to 60.

Then the area of the triangle ABC is equal to:

Saavs = AB * BC * Sin60 / 2 = AB2 * Sin60 / 2.

AB2 = 2 * Savs / Sin60 = 2 * 3 * √3 / (√3 / 2) = 12.

AB = √12 = 2 * √3 cm.

The radius of the circumscribed circle about a regular triangle is:

R = AB / √3 = 2 * √3 / √3 = 2 cm.

Answer: The radius of the circumscribed circle is 2 cm.



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